Okay, it's been a few years since I was last in a math class, but this is doable...
There are 4 aces in a deck of 52 -- 1/13 odds of being dealt an ace in one turn. The odds of getting a deuce in a single turn are the same. However, the odds of getting them consecutively in two turns requires those odd to be multiplied -- 13x13 = 169 or 1/169. Now, since we are dealt four cards, and not just two, our chances of getting the desired cards are doubled to 2/169 or roughly 1.2% of the time. But consider this... each player has those odd of 1.2%. So if there are 8 players at the table, the odds are approaching 1 in 10 that SOMEONE at the table will have an ace/deuce.This all assumes that my rusty math is good. Anyone confirm this? |